Class 9th math 1.1 solution english PCTB

Question 3: \((i) \quad 0.\overline{21} \)

Solution:

Let\(\qquad\) \(x=0.\overline{21}\)

\[x=0.212121…\_\_\_\_\_\_(1)\]

Multiplying equation \((1)\) by \(100\)

\[100x=21.212121…\_\_\_\_\_\_(2)\]

Subtract equation \((1)\) from equation \((2)\), we have

\[100x-x=21.212121…-0.212121…\]

\[99x=21\]

\[x=\frac{21}{99}\]

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