Question 6: \((iii)\) \(\frac{3}{5}\) and \(\frac{4}{5}\)
Solution:
1st Rational Number: Average of \(\frac{3}{5}\) and \(\frac{4}{5}\)
\[\begin{align*}
& =\left(\frac{3}{5}+\frac{4}{5}\right)\div 2\\
& =\left(\frac{3+4}{5}\right)\div 2 \\
& =\frac{7}{5}\times \frac{1}{2}\\
& =\frac{7}{10}\\
\end{align*}\]
2nd Rational Number: Average of \(\frac{3}{5}\) and \(\frac{7}{10}\)
\[\begin{align*}
& =\left(\frac{3}{5}+\frac{7}{10}\right)\div 2\\
& =\left(\frac{6+7}{10}\right)\div 2\\
& =\frac{13}{10}\times \frac{1}{2}\\
& =\frac{13}{20}\\
\end{align*}\]
——-OR——-
Average of \(\frac{4}{5}\) and \(\frac{7}{10}\)
\[\begin{align*}
&=\left(\frac{4}{5}+\frac{7}{10}\right)\div 2\\
& =\left(\frac{8+7}{10}\right)\div 2\\
& =\frac{15}{10}\times \frac{1}{2}\\
& =\frac{15}{20}\\
\end{align*}\]