Class 9th math 1.1 solution english New

This is the Solution of exercise 1.1 from newly published book by PCTB (Punjab) for new 9th session 2025 Onward.

Exercise 1.1

Question # 01: Identify each of the following as rational or irrational number.

Question 2: Represent the following numbers on number line.

Question 3: Express the following as a rational number \(\frac{p}{q}\) where \(p\) and \(q\) are integers and \(q\ne 0 \).

Question 4: Name the property used in the following.

\((i)\) \(\quad \left(a+4\right)+b=a+\left(4+b\right) \)

\((ii)\) \(\quad \sqrt{2} +\sqrt{3} =\sqrt{3} +\sqrt{2} \)

\((iii)\) \(\quad x-x=0 \)

\((iv)\) \(\quad a\left(b+c\right)=ab+ac \)

\((v)\) \(\quad 16+0=16 \)

\((vi)\) \(\quad 100\times1=100 \)

\((vii)\) \(\quad 4\times \left(5 \times 8\right) = \left(4\times 5\right) \times 8 \)

\((viii)\) \(\quad ab=ba \)

Question 5: Name the property used in the following.

\((i)\) \(\quad -3< -1\ \Rightarrow \ 0< 2 \)

\((ii)\) \(\quad\) If \(a< b\) then \(\frac{1}{a} >\frac{1}{b}\)

\((iii)\) \(\quad\) If \(a<b\) then \(a+c< b+c\)

\((iv)\) \(\quad \) If \(ac<bc\) and \(c>0\) then \(a<b\)

\((v)\) \(\quad\) If \(ac<bc\) and \(c<0\) then \(a>b\)

\((vi)\) \(\quad\) Either \(a>b\) or \(a=b\) or \(a<b\)

Question 6: Insert two rational numbers between:

\((i)\) \(\quad\) \(\frac{1}{3}\) and \(\frac{1}{4}\)

\((ii)\) \(\quad\) \(3\) and \(4\)

\((iii)\) \(\quad\) \(\frac{3}{5}\) and \(\frac{4}{5}\)

Leave a comment