Class 9th math 1.1 solution english PCTB

Question 3: \((ii) \quad 0.\overline{37} \)

Solution:

Let\(\qquad\) \(x=0.\overline{37}\)

\[x=0.373737…\_\_\_\_\_\_(1)\]

Multiplying equation \((1)\) by \(100\)

\[ 100x=37.373737…\_\_\_\_\_\_(2)\]

Subtract equation \((1)\) from equation \((2)\), we have

\[100x-x=37.373737…-0.373737…\]

\[99x=37\]

\[x=\frac{37}{99}\]

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