Sat Absolute Value Practice Problems

Questions related to basic arithmetic involving absolute values.

\(Q1.\quad |-2|=\_\_\_\_ \)

\( a) \qquad 2 \)

\( b) \quad -2\)

\(c) \qquad 0 \)

\( d) \qquad \text{Both a and b} \)

\( \text{Answer/Explanation}\)

\(Q2.\quad -|-3|=\_\_\_\_ \)

\( a) \qquad 3 \)

\( b) \quad -3\)

\(c) \qquad 0 \)

\( d) \qquad \text{Both a and b} \)

\( \text{Answer/Explanation}\)

\(Q3.\quad |-2+5-2\times 7|=\_\_\_\_ \)

\( a) \qquad 7 \)

\( b) \quad -7\)

\(c) \quad -11 \)

\( d) \qquad 11 \)

\( \text{Answer/Explanation}\)

\(Q4.\quad |-11|+|11|=\_\_\_\_ \)

\( a) \qquad 22 \)

\( b) \quad -22\)

\(c) \qquad 0 \)

\( d) \qquad \text{None of these} \)

\( \text{Answer/Explanation}\)

\(Q5.\quad |-13|\times |2|=\_\_\_\_ \)

\( a) \qquad 26 \)

\( b) \qquad -26\)

\(c) \qquad 15 \)

\( d) \qquad -11 \)

\( \text{Answer/Explanation}\)

\(Q6.\quad \frac{|-15|}{|3|}=\_\_\_\_ \)

\( a) \qquad 5 \)

\( b) \quad -5\)

\(c) \qquad 0 \)

\( d) \qquad \text{Not possible} \)

\( \text{Answer/Explanation}\)

\(Q7.\quad \frac{-|3|\times -|6|}{|-2|\times |-3|}=\_\_\_\_ \)

\( a) \quad -3 \)

\( b) \qquad 3\)

\(c) \qquad 2 \)

\( d) \qquad 1.5 \)

\( \text{Answer/Explanation}\)

\(Q8.\quad \frac{|-2|-|3|\times |-3|}{-|-3|-|-3|}=\_\_\_\_ \)

\( a) \qquad 0.7 \)

\( b) \quad -0.7\)

\(c) \qquad 1.5 \)

\( d) \quad -1.5 \)

\( \text{Answer/Explanation}\)

\(Q9.\quad \frac{( |-2|)^{3} \times ( -|2|)^{7}}{-( |2|)^{5} \times ( |2|)^{4}} \text{ is equivalent to} \)

\( a) \qquad |2| \)

\( b) \quad -|2|\)

\(c) \qquad |2|^{19} \)

\( d) \quad -|2|^{19} \)

\( \text{Answer/Explanation}\)

\(Q10.\quad \sqrt{\left |\frac{( -32) \times ( -64)}{( -512)}\right |} \text{ is equal to }\)

\( a) \qquad 2 \)

\( b) \qquad 2i\)

\(c) \quad -2 \)

\( d) \quad -2i \)

\( \text{Answer/Explanation}\)

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