Class 9th math Review Exercise 3 solution english PCTB

Question # 01: Four option are given against each statement. Encircle the correct option.

\((vi)\) If \(n( A\cup B)=50\), \(n( A) =30\) and \(n( B) =35\), then \(n( A\cap B) =\) :

\( a) \quad \) \( 23\)

\( b) \quad \) \( 15\)

\(c) \quad \) \( 9\)

\( d) \quad \) \( 40\)

Answer: \( b) \; \) \( 15\)


Explanation:

Since

\(n(A\cup B)=n(A)+n(B)-n(A\cap B)\)

After rearranging, we get

\(n(A\cap B)=n(A)+n(B)-n(A\cup B)\)

\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =30+35-50\)

\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =15\)

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