Class 9th math Review Exercise 3 solution english PCTB

Question # 01: Four option are given against each statement. Encircle the correct option.

\((viii)\)\(\;\)If \(f(x)=x^2-3x+2\), then the value of \(f(a+1)\) is equal to:

\( a) \quad \) \( a+1\)

\( b) \quad \) \( a^2+1\)

\(c) \quad \) \( a^2+2a+1\)

\( d) \quad \) \( a^2-a\)

Answer: \( d) \; \) \( a^2-a\)


Explanation:

\(f(x)=x^2-3x+2\)

\(f(a+1)=(a+1)^2-3(a+1)+2\)

\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =a^2+1^2+2a-3a-3+2\)

\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =a^2+1-a-1\)

\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =a^2-a\)

Leave a comment