Class 9th math Review Exercise 3 solution english PCTB

Question 6: Verify the properties for the sets \(A\), \(B\) and \(C\) given below:

\((b)\) \(\;\) \(A=\phi\), \(B=\{0\}\), \(C=\{0,1,2\}\)

\((i)\) Associative of Union

\((ii)\) Associativity of intersection

\((iii)\) Distributive of Union over intersection

\((iv)\) Distributive of intersection over union

Solution:

\((i)\) Associative of Union

\((A\cup B)\cup C=A\cup (B\cup C)\) is Associative of Union

\(\text{L.H.S.}=(A\cup B)\cup C\)

\(\ \ \ \ \ \ \ \ \ \ \ =[\{\}\)\(\cup\)\(\{0\}]\)\(\cup\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{0\}\)\(\cup\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{0,1,2\}\)

\(\text{R.H.S.}=A\cup (B\cup C)\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cup\)\([\{0\}\)\(\cup\)\(\{0,1,2\}]\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cup\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{0,1,2\}\)

Hence, \(\text{L.H.S.}=\text{R.H.S.}\)

\((ii)\) Associativity of intersection

\((A\cap B)\cap C=A\cap (B\cap C)\) is Associative of Intersection

\(\text{L.H.S.}=(A\cap B)\cap C\)

\(\ \ \ \ \ \ \ \ \ \ \ =[\{\}\)\(\cap\)\(\{0\}]\)\(\cap\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cap\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)

\(\text{R.H.S.}=A\cap (B\cap C)\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cap\)\([\{0\}\)\(\cap\)\(\{0,1,2\}]\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cap\)\(\{0\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)

Hence, \(\text{L.H.S.}=\text{R.H.S.}\)

\((iii)\) Distributive of Union over intersection

\(A \cup (B \cap C) = (A \cup B) \cap (A \cup C)\) is Distributive of Union over intersection

\(\text{L.H.S.}=A \cup (B \cap C)\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cup\)\([\{0\}\)\(\cap\)\(\{0,1,2\}]\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cup\)\(\{0\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{0\}\)

\(\text{R.H.S.}=(A \cup B) \cap (A \cup C)\)

\(\ \ \ \ \ \ \ \ \ \ \ =[\{\}\)\(\cup\)\(\{0\}]\)\(\cap\)\([\{\}\)\(\cup\)\(\{0,1,2\}]\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{0\}\)\(\cap\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{0\}\)

Hence, \(\text{L.H.S.}=\text{R.H.S.}\)

\((iv)\) Distributive of intersection over union

\(A \cap (B \cup C) = (A \cap B) \cup (A \cap C)\) is Distributive of intersection over union

\(\text{L.H.S.}=A \cap (B \cup C)\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cap\)\([\{0\}\)\(\cup\)\(\{0,1,2\}]\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cap\)\(\{0,1,2\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)

\(\text{R.H.S.}=(A \cap B) \cup (A \cap C)\)

\(\ \ \ \ \ \ \ \ \ \ \ =[\{\}\)\(\cap\)\(\{0\}]\)\(\cup\)\([\{\}\)\(\cap\)\(\{0,1,2\}]\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)\(\cup\)\(\{\}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\{\}\)

Hence, \(\text{L.H.S.}=\text{R.H.S.}\)

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