Class 9th math Review Exercise 1 solution english PCTB

Question 8: The sum of three consecutive odd integers is \(51\). Find the three integers.

Solution:

Let \(x-2\), \(x\), and \(x+2\) are three consecutive odd integers

According to the given condition of question

\[\begin{align*} x-2+x+x+2&=51\\
3x&=51\\
x&=\frac{51}{3}\\
x&=17\\
\end{align*}\]

So, \(15\), \(,17\), and \(19\) are required numbers

——– Alternate Method ——–

Let \(x\), \(x+2\), and \(x+4\) are three consecutive odd integers

According to the given condition of question

\[\begin{align*} x+x+2+x+4&=51\\
3x+6&=51\\
3x&=51-6\\
3x&=45\\
x&=\frac{45}{3}\\
x&=15\\
\end{align*}\]

So, \(15\), \(,17\), and \(19\) are required numbers

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