Question # 01: Find HCF by factorization method:
\((ii)\) \(\;\) \(4x^2-9y^2,2x^2-3xy\)
Solution:
$\displaystyle 4x^{2} -9y^{2} =( 2x)^{2} -( 3y)^{2}$
$\displaystyle\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =( 2x-3y)( 2x+3y)$
$\displaystyle 2x^{2} -3xy=x( 2x-3y)$
$\displaystyle \text{HCF} =2x-3y$