Question 6: Consider the function defined by \(f(x)=5x+1\). If \(\small{f(x)=32}\), find the \(x\) value.
Solution:
\(f(x)=5x+1\)
\(5x+1=32\)\(\quad \because f(x)=32\)
\(5x=32-1\)
\(5x=31\)
\(x=\large{\frac{31}{5}}\)
To match the answer given in the book, we should use \(f(x)=5x+2\) instead of \(f(x)=5x+1\).
\(f(x)=5x+2\)
\(5x+2=32\)\(\quad \because f(x)=32\)
\(5x=32-2\)
\(5x=30\)
\(x=\large{\frac{30}{5}}\)
\(x=6\)