Class 9th math 3.3 solution english PCTB

Question 3: If \(g(x)=3x+2\) and \(h(x)=x^2+1\), then find:

\((vi)\) \(\; \) \(h(\large{-\frac{1}{2}})\)

Solution:

\(h(x)=x^2+1\)

\(h(\large{-\frac{1}{2}})=(\large{-\frac{1}{2}})^2+1\)

\(\ \ \ \ \ \ \ \ \ \ \ =\large{\frac{1}{4}}+1\)

\(\ \ \ \ \ \ \ \ \ \ \ =\large{\frac{1+4}{4}}\)

\(\ \ \ \ \ \ \ \ \ \ \ =\large{\frac{5}{4}}\)

Leave a comment