Class 9th math Review Exercise 2 solution english PCTB

Question # 01: Four option are given against each statement. Encircle the correct option.

\((vi)\) If \(log\ 2=0.3010\), then \(log\ 200\) is:

Answer: Option (c) \( 2.3010\) is correct option.

\[
\begin{align*}
&=\log200\\
&=\log(2\times10^2) \\
&=\log2+\log10^2\\
&=0.3010+2\log10\\
&=0.3010+2\\
&=2.3010\\
\end{align*}
\]

** You can also find \(\log200\) using calculator directly.

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