Class 9th math 4.4 solution english PCTB

Question # 01: Find the square root of the following polynomials by factorization method:

\((i)\) \(\;\) \( x^2-8x+16\)

Solution:

$=x^{2} -8x+16$

$=x^{2} -2( x)( 4) +4^{2}$

$\displaystyle =( x-4)^{2}$

Taking square root, we have

$ $$\sqrt{x^{2} -8x+16} =\pm \sqrt{( x-4)^{2}}$

$\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\pm ( x-4)$

——– Alternate Method ——–

$=x^{2} -8x+16$

$=x^{2} -4x-4x+16$

$=x( x -4) -4( x-4)$

$=( x-4)( x-4)$

$\displaystyle =( x-4)^{2}$

Taking square root, we have

$ $$\sqrt{x^{2} -8x+16} =\pm \sqrt{( x-4)^{2}}$

$\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\pm ( x-4)$

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