Class 9th math 4.2 solution english PCTB

Question 4: Factorize:

\((iv)\) \(\; \)\(1000a^3+1 \)

Solution:

$\displaystyle \ \ \ \ 1000a^{3} +1$

$\displaystyle =( 10a)^{3} +1^{3}$

$\displaystyle =( 10a+1)\left[( 10a)^{2} -( 10a)( 1) +1^{2}\right]$

$\displaystyle =( 10a+1)\left( 100a^{2} -10a+1\right)$

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