Class 9th math 4.2 solution english PCTB

Question 4: Factorize:

\((i)\) \(\;\) \( 125a^3-1\)

Solution:

$\displaystyle \ \ \ \ 125a^{3} -1$

$\displaystyle =( 5a)^{3} -1^{3}$

$\displaystyle =( 5a-1)\left[( 5a)^{2} +( 5a)( 1) +1^{2}\right]$

$\displaystyle =( 5a-1)\left( 25a^{2} +5a+1\right)$

Leave a comment