Question 3: Factorize:
\((ii)\) \(\;\) \(27a^3+108a^2b+144ab^2+64b^3\)
Solution:
$\displaystyle \ \ \ \ 27a^{3} +108a^{2} b+144ab^{2} +64b^{3}$
$\displaystyle =( 3a)^{3} +3( 3a)^{2}( 4b) +3( 3a)( 4b)^{2} +( 4b)^{3}$
$\displaystyle =( 3a+4b)^{3}$
Question 3: Factorize:
\((ii)\) \(\;\) \(27a^3+108a^2b+144ab^2+64b^3\)
Solution:
$\displaystyle \ \ \ \ 27a^{3} +108a^{2} b+144ab^{2} +64b^{3}$
$\displaystyle =( 3a)^{3} +3( 3a)^{2}( 4b) +3( 3a)( 4b)^{2} +( 4b)^{3}$
$\displaystyle =( 3a+4b)^{3}$