Class 9th math 3.1 solution english PCTB

Question 6: What is the number of elements of the power set of each of the following sets?

\((iv)\) \(\;\) \(\{\{a,b\},\{b,c\},\{d,e\}\}\)

Solution:

\(n=3\)

\(2^3=8\)

There are \(8\) element in the power set.


Explanation:

If a set has \(n\) elements, then the number of elements in its power set is \(2^n\).

First element: \(\{a,b\}\) \(\quad\) Second element: \(\{b,c\}\) \(\quad\) Third element: \(\{d,e\}\)

In this case there are 3 element. So, \(n=3\) and we have \(2^3=8\) number of elements in the power set.

Leave a comment