Question 4: Find the value of \(x\) in the following equations:
\((i)\) \(\quad\) \(log\ 2+log\ x=1 \)
Solution:
\[
\begin{align*}
\log 2+\log x&=1\\
\log x&=1-\log 2\\
\log x&=1-0.3010\\
\log x&=0.699
\end{align*}
\]
Taking antilog on both sides, we have
\[
\begin{align*}
x&=\text{antilog}( 0.699)\\
x&=5
\end{align*}
\]