Class 9th math 2.3 solution english PCTB

Question 4: Find the value of \(x\):

\((ii)\) \(\quad\) \(log\ x = 1.192\)

Solution:

\[log\ x = 1.192\]

Taking antilog on both sides

\[\text{anti-log}(\text{log}x)=\text{anti-log}(1.192)\]

\[x=15.56\]